105 lines
2.5 KiB
C++
105 lines
2.5 KiB
C++
#include "tap.hpp"
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#include "parallel/queue.hpp"
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#include "thread/flag.hpp"
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#include "thread/semaphore.hpp"
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#include "view.hpp"
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#include <algorithm>
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#include <thread>
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static constexpr uint32_t slots = 4;
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static constexpr int parallelism = 8;
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static constexpr int chunk_size = 1<<12;
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cruft::thread::flag start;
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using queue_t = cruft::parallel::queue<int,slots>;
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///////////////////////////////////////////////////////////////////////////////
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// push numbers in the range [first,first+chunk_size) to the queue
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void
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produce (queue_t &dst, const int first)
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{
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start.wait ();
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for (int i = first; i < first + chunk_size; ++i)
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while (!dst.push (i))
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;
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}
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//-----------------------------------------------------------------------------
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// pop chunk_size elements from the queue to a vector
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void
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consume (queue_t &src, cruft::view<int*> dst)
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{
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(void)dst;
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start.wait ();
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int last;
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for (int i = 0; i < chunk_size; ++i) {
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while (!src.pop (last))
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;
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dst[i] = last;
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}
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}
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///////////////////////////////////////////////////////////////////////////////
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// * create n producers which push the c integers over [n*c,n*(c+1)) into a queue
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// * create n consumers which pop c integers from a queue into a store
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// * ensure all integers we expected are in the store
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//
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// we use an artificially small queue size to force contention.
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//
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// to stress test we increase the threads, increase the data length, and
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// decrease the queue size.
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int
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main ()
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{
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cruft::TAP::logger tap;
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queue_t src;
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// start n consumers, and n producers that fill an array with integers
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std::vector<int> dst (parallelism * chunk_size);
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std::vector<std::thread> consumers;
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std::vector<std::thread> producers;
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for (int i = 0; i < parallelism; ++i) {
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consumers.emplace_back (
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consume,
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std::ref (src),
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cruft::view{
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dst.data() + i * chunk_size,
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chunk_size
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}
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);
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producers.emplace_back (produce, std::ref (src), i * chunk_size);
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}
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start.notify_all ();
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// wait for everyone to complete
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for (auto &t: producers)
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t.join ();
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for (auto &t: consumers)
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t.join ();
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// sort the result and ensure all values are present
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std::sort (dst.begin (), dst.end ());
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int missing = 0;
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for (int i = 0; i < parallelism * chunk_size; ++i)
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if (dst[i] != i)
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++missing;
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tap.expect_eq (missing, 0, "no lost values in parallel produce/consume queue");
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return tap.status ();
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}
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