libcruft-util/crypto/xtea.cpp

85 lines
2.3 KiB
C++

/*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*
* Copyright 2015 Danny Robson <danny@nerdcruft.net>
*/
#include "xtea.hpp"
using util::crypto::XTEA;
///////////////////////////////////////////////////////////////////////////////
static const uint32_t MAGIC = 0x9E3779B9;
// each iteration performs two feistel rounds, for a total of 64
static const unsigned ITERATIONS = 32;
///////////////////////////////////////////////////////////////////////////////
XTEA::XTEA (key_t _key):
m_key (_key)
{ }
//-----------------------------------------------------------------------------
void
XTEA::encrypt (uint32_t *restrict data, size_t count)
{
if (count % 2)
throw std::invalid_argument ("XTEA requires even data count");
auto last = data + count;
while (data < last) {
uint32_t sum = 0;
uint32_t v0 = data[0];
uint32_t v1 = data[1];
for (unsigned i = 0; i < ITERATIONS; ++i) {
v0 += (((v1 << 4) ^ (v1 >> 5)) + v1) ^ (sum + m_key[sum & 3]);
sum += MAGIC;
v1 += (((v0 << 4) ^ (v0 >> 5)) + v0) ^ (sum + m_key[(sum >> 11) & 3]);
}
*data++ = v0;
*data++ = v1;
}
}
//-----------------------------------------------------------------------------
void
XTEA::decrypt (uint32_t *restrict data, size_t count)
{
if (count % 2)
throw std::invalid_argument ("XTEA requires even data count");
auto last = data + count;
while (data < last) {
uint32_t sum = ITERATIONS * MAGIC;
uint32_t v0 = data[0];
uint32_t v1 = data[1];
for (unsigned i = 0; i < ITERATIONS; ++i) {
v1 -= (((v0 << 4) ^ (v0 >> 5)) + v0) ^ (sum + m_key[(sum >> 11) & 3]);
sum -= MAGIC;
v0 -= (((v1 << 4) ^ (v1 >> 5)) + v1) ^ (sum + m_key[sum & 3]);
}
*data++ = v0;
*data++ = v1;
}
}